What will be output of the following c code?

#include<stdio.h>
const enum Alpha
    {
      X,
      Y=5,
      Z
    }p=10;
int main()
{
    enum Alpha a,b;
    a= X;
    b= Z;
    printf("%d",a+b-p);
    return 0;
   }

A) 5

B) 4

C) -4

D) -5

Default value of enum constant X is zero and
Z = Y + 1 = 5 + 1 = 6
So, a + b – p
=0 + 6 -10 = -4

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What will be output of the following c code?#include<stdio.h>const enum Alpha { X, Y=5, Z }p=10;int main() { enum Alpha a,b; a= X; b= Z; printf("%d",a+b-p); return 0; }